A horizontal conveyor belt moves with a constant velocity `V.A` small block is projected with a velocity of `6m//s` on it in a direction opposite to the direction of motion of the belt The block comes to rest relative to the belt in a time `4s. mu =0.3, g =10 .m//s^(2)` Find `V` .

A horizontal converyor belt moves with a constant velocity V. A small block is projected with a velocity of 6 mis on it in a direction opposite to the direction of motion of the belt. The block comes to rest relative to the belt in a time 4s. mu = 0.3 g, g= 10 m//s^(2) Find V

A horizontal converyor belt moves with a constant velocity V. A small block is projected with a velocity of 6 mis on it in a direction opposite to the direction of motion of the belt. The block comes to rest relative to the belt in a time 4s. mu = 0.3 g, g= 10 m//s^(2) Find V

In the block moves up with constant velocity v m/s. Find F

A block lying on a long horizontal conveyer belt moving at a constant velocity receives a velocity v_(0) = 5m//s relative to the ground in the direction opposite to the direction of motion of the conveyer. After t = 4s , the velocity of the block becomes equal to the velocity of the belt. The coefficient of friction between the block and the belt is mu = 0.2 . Determine the velocity v of the conveyer belt.

A conveyor belt is moving with constant speed of 6 m//s . A small block is just dropped on it.Coefficient of friction between the two is mu = 0.3 . Find (a) The time when relative motion between them will stop (b) Displacement of block upto that instant (g = 10 m//s^(2)) .

A conveyor belt is moving with constant speed of 6 m//s . A small block is just dropped on it.Coefficient of friction between the two is mu = 0.3 . Find (a) The time when relative motion between them will stop (b) Displacement of block upto that instant (g = 10 m//s^(2)) .