Biot Savart Law, Magnetic field of a str...

Biot Savart Law, Magnetic field of a straight wire

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According to Biot-Savarat's law, magentic field due to a straight current carrying wire at a point at a distance r form it is given by B=(mu_0I)/(4pir)(sinphi_1+sinphi_2) The direction of magnetic field being perpendicular to the plane containing the wire and the point. Figure, shows a closed loop AOCBA in which current I is flowing as shown. Given OA=OB=OC=a . Find the magnetic field at point B due to this loop.

`-(mu_0I)/(4pi(sqrt2a)) (hati+hatj)`

`-(mu_0I)/(4pi(sqrt2a)) (hatj+hati)`

`(-mu_0I)/(2(sqrt2pi)) (hatj+hati)`

none of these

According to Biot-Savarat's law, magentic field due to a straight current carrying wire at a point at a distance r form it is given by B=(mu_0I)/(4pir)(sinphi_1+sinphi_2) The direction of magnetic field being perpendicular to the plane containing the wire and the point. Find magnetic field at point O in Fig.

`-(mu_0I)/(4pia) (hati+hatk)`

`-(mu_0I)/(4pia) (hatj+hatk)`

`-(-mu_0I)/(2pia) (hatj+hatk)`

`(-mu_0I)/(2sqrt2pia) (hatj+hatk)`

The strength of the magnetic field around a long straight wire, carrying current, is

inversely proportional to the distance from the wire

inversely proportional to the square of the distance from the wire

directly proportional to the square of the distance

directly proportional to the distance from the wire

Biot Savart Law, Magnetic field of a straight wire

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