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The number of four letters word while ea...

The number of four letters word while each consisting 2 distinct and two alike letters taken from eord `SYLLABUS`

A

240

B

144

C

288

D

432

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of four-letter words consisting of two distinct letters and two alike letters taken from the word "SYLLABUS," we can follow these steps: ### Step 1: Identify the Letters The word "SYLLABUS" consists of the following letters: - S (occurs 2 times) - Y (occurs 1 time) - L (occurs 2 times) - A (occurs 1 time) - B (occurs 1 time) - U (occurs 1 time) From this, we can see that we have: - 2 alike letters (either S or L) - 2 distinct letters (from the remaining letters) ### Step 2: Choose the Distinct Letters We need to choose 2 distinct letters from the available letters. The distinct letters available are S, Y, L, A, B, and U. However, since we need to consider that S and L can also be the alike letters, we will treat them as distinct for this step. The total distinct letters we can choose from are: - S, Y, L, A, B, U (total of 6 letters) We will choose 2 distinct letters from these 6 letters. The number of ways to choose 2 distinct letters from 6 is given by the combination formula: \[ \text{Number of ways to choose 2 distinct letters} = \binom{6}{2} = 15 \] ### Step 3: Choose the Alike Letter Now, we need to choose one letter to be the alike letter. The possible alike letters can be either S or L. Therefore, we have: - If we choose S as the alike letter, we can choose one of the remaining distinct letters (which we have already chosen). - If we choose L as the alike letter, we can choose one of the remaining distinct letters (which we have already chosen). Thus, we have 2 choices for the alike letter. ### Step 4: Calculate the Total Combinations Now we multiply the number of ways to choose the distinct letters by the number of ways to choose the alike letter: \[ \text{Total combinations} = \binom{6}{2} \times 2 = 15 \times 2 = 30 \] ### Step 5: Arrange the Letters Now, we need to arrange the 4 letters (2 alike and 2 distinct). The arrangement of the letters can be done using the formula for permutations of multiset: \[ \text{Number of arrangements} = \frac{4!}{2!} = \frac{24}{2} = 12 \] ### Step 6: Final Calculation Finally, we multiply the total combinations by the number of arrangements: \[ \text{Total number of 4-letter words} = 30 \times 12 = 360 \] ### Conclusion Thus, the total number of four-letter words consisting of two distinct letters and two alike letters taken from the word "SYLLABUS" is **360**. ---
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