Home
Class 11
MATHS
if logkx.log5k = logx5 , k!=1 , k>0 , th...

if `log_kx.log_5k = log_x5` , `k!=1 , k>0` , then find the value of x

Promotional Banner

Similar Questions

Explore conceptually related problems

If log_(k)xlog_(5)k=3 , then find the value of x.

If (log)_k xdot(log)_5k=(log)_x5,k!=1,k >0, then x is equal to

If (log)_kx . (log)_5k=(log)_x5,k!=1,k >0, then x is equal to k (a) k (b) 1/5 (c) 5 (d) none of these

If log_(k)x*log_(5)k=log_(x)5,k!=1,k>0, then x is equal to k(b)1/5(c)5(d) none of these

If (log)_k xdot(log)_5k=(log)_x5,k!=1,k >0, then x is equal to k (b) 1/5 (c) 5 (d) none of these

If (log)_k xdot(log)_5k=(log)_x5,k!=1,k >0, then x is equal to k (b) 1/5 (c) 5 (d) none of these

If (log)_k xdot(log)_5k=(log)_x5,k!=1,k >0, then x is equal to (a) k (b) 1/5 (c) 5 (d) none of these

If (log_(5) K) (log_(3) 5) (log_(k) x ) = k , then the value of x if k = 3 is

If log_(5) log_(5) log_(3) x = 0 , then value of x is