If the lines `6x-2=3y+1=2z-2` and `(x-2)/(lamda)=(2y-5)/(-3),z=-2` are perpendicular then `lamda=`

If the lines 6x-2 = 3y +1 = 2z-2 and (x-2)/l = (2y-5)/-3 , z=-2 are mutually perpendicular, then: l=

The value of lamda for which the lines (x-1)/1=(y-2)/(lamda)=(z+1)/(-1) and (x+1)/(-lamda)=(y+1)/2=(z-2)/1 are perpendicular to each other is

The value of lamda for which the lines (x-1)/1=(y-2)/(lamda)=(z+1)/(-1) and (x+1)/(-lamda)=(y+1)/2=(z-2)/1 are perpendicular to each other is

If the planes 2x-y+lamdaz-5=0 an x+4y+2z-7=0 are perpendicular then lamda=

If the planes 2x-y+lamdaz-5=0 an x+4y+2z-7=0 are perpendicular then lamda=

If the lines (x-1)/(-3)=(y-2)/(2lamda)=(z-3)/(2)" and "(x-1)/(3lamda)=(y-1)/(1)=(z-6)/(-5) are perpendicular to each other, then find lamda

If line (2x-4)/(lamda)=(lamda-1)/(2)=(z-3)/(1) and (x-1)/(1)=(3y-1)/(lamda)=(z-2)/(1) are perpendicular to each then lamda= . . .

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(6)are

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are