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wedge (eq) of 0.10N solution of CaI(2) i...

`wedge _(eq)` of `0.10N` solution of `CaI_(2)` is `100.0 Scm^(2)eq^(-1)` at `298 K.G^(**)` of the cell `=0.25 cm^(-1)`. How much current will flow potential difference between the electrode is `5V` ?

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