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If (cosx)/a=(cos(x+theta))/b=(cos(x+20))...

If `(cosx)/a=(cos(x+theta))/b=(cos(x+20))/c=(cos(x+3theta))/d` then `(a+c)/(b+d)` is equal to (a)`a/d` (b) `c/b` (c) `b/c` (d) `d/a`

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