If `x=2costheta-cos2\ theta` and `y=2sintheta-sin2\ theta` , prove that `(dy)/(dx)=tan((3theta)/2)`

If x=2cos theta-cos2 theta and y=2sin theta-sin2 theta, prove that (dy)/(dx)=tan((3 theta)/(2))

If x=2cos theta-cos2 theta and y=2sin theta-sin2 theta then prove that (dy)/(dx)=tan((3 theta)/(2))

If =2cos theta-cos2 theta and y=2sin theta-sin2 theta Prove that (dy)/(dx)=tan((3 theta)/(2))

If x=2cos theta-cos 2theta and y=2sin theta-sin 2 theta , then prove that (dy)/(dx)=tan((3theta)/(2))

If x=2costheta-cos2theta"and"y=2sintheta-sin2theta" Prove that" (dy)/(dx)=tan((3theta)/2)dot

If x=2costheta-cos2theta"and"y=2sintheta-sin2theta" Prove that" (dy)/(dx)=tan((3theta)/2)dot

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

If x = 2 cos theta - cos 2theta and y = 2 sin theta - sin 2theta then prove that : (dy)/(dx)=tan (3 theta)/(2)