A ball released from rest from the roof of a building of height 45 m at t = 0. Find the height of ball from ground at t = 2s.

A ball is released from the top of a building of height 45m at t=0 . When the ball strikes the ground, its speed becomes (2)/(3) times its original value. The time instant when the ball strikes the ground for the second time is t = ...........sec . ["Take" g=10 m//s^(2) ]

A ball is thrown vertically upwards from the top of a building of height 29.4m and with an initial velocity 24.5 m/sec. If the height H of the ball from the ground level is given by H = 29.4 + 24.5t - 4.9t^(2) , then find the time taken by the ball to reach the ground.

A ball is dropped from the top of a building of height 80 m. At same instant another ball is thrown upwards with speed 50 m/s from the bottom of the building. The time at which balls will meet is

A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?

A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?