`x=a(theta-sintheta),y=a(1+costheta)`

Find dy/dx , if x and y are connected parametrically by the equations, given below without eliminating the parameter: x=a(theta-sintheta),y=b(1+costheta)

Find (dy)/(dx) when x=a(theta-sintheta),y=b(1-costheta) .

if x = a(theta-sintheta), y=(1+costheta) , then (dy)/(dx) is equal to

Find (dy)/(dx) , if x=a(theta+sintheta), y=1(1-costheta) .

Find (dy)/(dx) , if x=a(theta+sintheta), y=1(1-costheta) .

Find dy/dx if x=a(theta-sintheta) and y=a(1+costheta)

If x=a(theta-sintheta) and, y=a(1+costheta) , find (dy)/(dx) at theta=pi/3 .

If y=a(theta+sintheta),x=a(1-costheta)," then "(dy)/(dx)=

Find (dy)/(dx) if x=a(theta-sintheta) and y=a(1-costheta) .

Find (dy)/(dx) if x=a(theta-sintheta) and y=a(1-costheta) .