If origin is shifted to the point `(2,3)` then what will be the transformed equation of the straight line `2x-y+5=0` in the new `XY`-axes ?

If origin is shifted to the point (-1,2) then what will be the transformed equation of the curve 2x^(2)+y^(2)-3x+4y-1=0 in the new axes ?

If origin is shifted to the point (-1,2) then what will be the transformed equation of the curve 2x^(2)+y^(2)-3x+4y-1=0 in the new axes ?

If origin is shifted to the point (a,b) then what will be the transformed equation of the curve (x-a)^(2)+(y-b)^(2)=r^(2) ?

If origin is shifted to the point (a,b) then what will be the transformed equation of the curve (x-a)^(2)+(y-b)^(2)=r^(2) ?

If the origin is shifted to the point (1,2) then what will be the transform equation of the following equations, it is given that the new and old axes are parallel : (i) x^(2)+y^(2)-2x-4y=0 (ii) 2x^(2)-y^(2)-4x+4y-3=0 (iii) x^(2)+xy-2y^(2)-4x+7y-5=0 (iv) 3x+y=6

When the origin is shifted to the point (5,-2) then the transformed equation of the curve xy+2x-5y+11=0 is XY=K then k is

What will be the new equation of straight line 3x + 4y = 6 if the origin gets shifted to (3, - 4)?

If the origin is shifted to the point (2,-3) the axes remaining parallel,find the new equation of the locus in each of the following: xy-x-y+1=0