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In DeltaO P Q, right-angled at P, O P\ ...

In `DeltaO P Q`, right-angled at P, `O P\ =\ 7\ c m` and`O Q\ -\ P Q\ =\ 1\ c m`Determine the values of `sin\ Q\ a n d\ cos\ Qdot`

Text Solution

Verified by Experts

In `triangle OPQ` we get,
`(OQ)^2= (OP)^2+(PQ)^2`
`=> (PQ+1)^2=(OP)^2+(PQ)^2` [ Since `(OQ)-(PQ)= 1 => OQ=1+PQ`]
`=> (PQ)^2+2(PQ)+1=(OP)^2+(PQ)^2`
...
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