Resistance `R_1`and `R_2`, each `60 Omega`, are connected in series. The points `A` and `B` is `120 V`. Find the reading of voltmeter connected resistance `r=120Omega`

Resistance R_1 and R_2 , each 60 Omega , are connected in series. The Potential difference between points A and B is 120 V . Find the reading of voltmeter connected resistance r=120Omega

Resistances R_(1) and R_(2) , each 600 Omega , are connected in series as shown in figure-3.382. The potential difference between points A and B is 120 V. Find the reading of voltmeter connected between points C and D ifits resistance is 120 Omega

Resistances R_(1) and R_(2) each 60 are connected in series as shown in figure. The potential difference between A and B is kept 120 volt. Then what will be tha reading of voltmeter connected between thapoint C and D if resistance of voltmeter is 120 Omega ?

Two resistances R_1, and R_2, each of 100 Omega 22 Omega are connected with potential source of 40 V between A and B. If resistance of voltmeter is 200 Omega, then reading of voltmeter is

The resistance of 100 Omega and 200 Omega are connected in series with the 220 V mains. When a voltmeter of 1000 Omega resistance is connected in parallel to 100 Omega , then the reading of voltmeter is –

Resistance of 100 Omega and 200 Omega are connected in series with 220 V mains. When a voltmeter of 1000 Omega resistance is connected in parallel to 100 Omega , then the reading of voltmeter is

Resistance of 100 Omega and 200 Omega are connected in series with 220 V mains. When a voltmeter of 1000 Omega resistance is connected in parallel to 100 Omega , then the reading of voltmeter is

Two resistors 10Omega and 25Omega are connected in series and the combination is connected across a 25 V source of negligible internal resistance. A voltmeter of resistance 25Omega is connected across the 10Omega resistor. Find the reading in the voltmeter. If another voltmeter of a very large resistance replaces the voltmeter, then find the reading of voltmeter.

Two resistances R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega are connected in series . Find the equivalent resistance of the series combination.