Solve the equation:`x^2+3x+5=0`

Explanation

We know the roots of the quadratic equation `Ax^2+Bx+C=0 `are

`x=(−B±sqrt(B^2−4AC))/(2A)`

​​The given equation is
`x^2+3x+5=0`

for the given equation, `B^2−4AC=(3)^2−4(1)(5)=−11`

So the roots are

`x=((-3)±sqrt(−11))/(2)`

`x=((-3)±sqrt(-11))/(2)`

​​`x=(-3±sqrt(11)​i)/2`