Given `(1-2x+5x^2-10x^3)(1+x)^n=1+a_1x+a_2x^2+...` and that `a_1^2=2a_2` then `n=`

Given (1-2x+5x^2-10x^3)(1+x)^n=1+a_1x+a_2x^2+.... and that a_1^2=2a_2 , then the value of n is

Given (1-2x+5x^2-10 x^3)(1+x)^n=1+a_1x+a_2x^2+ and that a1 ^2=2a_2 then the value of n is.

Given (1-2x+5x^2-10 x^3)(1+x)^n=1+a_1x+a_2x^2+ and that a1 2=2a_2 then the value of n is.

Given (1-2x+5x^(2)-10x^(3))(1+x)^(n)=1+a_(1)x+a_(2)x^(2)+ and that a_(1)^(2)=2a_(2) then the value of n is.

If (1+2x +3x^2)^10 = a_0 +a_1x +a_2x^2 + ……+a_20x^20 then a_2/a_1 =

If (1+2x +3x^2)^10 = a_0 +a_1x +a_2x^2 + ……+a_20x^20 then a_1 = ?

If (1+x-x^2)^10/(1+x^2)=a_0+a_1x+a_2x^2+...+a_nx^n+… then find a_0+a_1+a_2+… .

If (1-px)^-1/((1-qx))=a_0+a_1x+a_2x^2+a_3x^3+....... then a_n=

If (1 - x + x^2)^n = a_0 + a_1x + a_2x^2 +...+ a_(2n) x^(2n) then a_0 + a_2 + a_4 +...+ a_(2n) is equal to