Three particles are projected upwards with initial speeds `10 m//s,20 m//s,30 m//s`. The displacements covered by them in their last second of motion are `x_(1),x_(2),x_(3)` then:

A particle is projected vertically upwards with an initial velocity of 40 m//s. Find the displacement and distance covered by the particle in 6 s. Take g= 10 m//s^2.

A particle is projected vertically upwards with an initial velocity of 40 m//s. Find the displacement and distance covered by the particle in 6 s. Take g= 10 m//s^2.

A body is projected with an initial elocity 20m/s at 60° to the horizontal. The displacement after 2 s is

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .

A particle is projected upwards with initial velocity u. assume acceleration due to gravity is 10m//s^(2) . It is found that particle covers 5m in last second before reaching the maximum height. What can be the possible value of u?