If x and y are connected parametrically by the equations given, without eliminating the parameter, Find `(dy)/(dx)`.
`x=costheta-cos2theta, y=sintheta-sin2theta`

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=cos theta-cos2 theta,y=sin theta-sin2 theta

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=acostheta, y=bcostheta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a cos theta,y=b cos theta

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=sin t,y=cos2t

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=sint , y=cos2t

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=a(theta-sintheta), y=a(1+costheta)

If x and y are connected parametrically by the equations without eliminating the parameter, find (dy)/(dx) x = cos theta - cos 2 theta, y= sin theta- sin 2 theta

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=a(costheta+thetasintheta), y=a(sintheta-thetacostheta)

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=asectheta, y=btantheta

If x and y are connected parametrically by the equation without eliminating the parameter, find (dy/dx) if x=cos theta-cos 2 theta, y=sin theta-sin 2 theta