Ground state energy of H-atom is `(-E_(1))`,t he velocity of photoelectrons emitted when photon of energy `E_(2)` strikes stationary `Li^(2+)` ion in ground state will be:

If the energy of H-atom in the ground state is-E, the velocity of photo-electron emitted when a photon having energy E_(rho) strikes a stationary Li^(2+) ion in ground state, is given by: v=sqrt((2(E_(rho)-E))/(m)) , v=sqrt((2(E_(rho)+9E))/(m)) , v=sqrt((2(E_(rho)-9E))/(m)) , v=sqrt((2(E_(rho)-3E))/(m))

If the energy of H-atom in the ground state is -E, the velocity of photo-electron emitted when a photon having energy E_p strikes a stationary Li^(2+) ion in ground state, is given by:

The ionisation energy o Li^(2+) atom in ground state is,

The ionisation energy of Li^(2+) atom in ground state is,

Calculate the ionisation energy of Li^(2+) atom in ground state.

What is the energy of the electron in He+ ion in the ground state ?

The ratio of energies of first excited state of He^+ ion and ground state of H^− atom is

The ground state energy of hydrogen atom is -13.6 eV . The energy of second excited state of He^(+) ion in eV is

The ground state energy of hydrogen atom is -13.6 eV . The energy of second excited state of He^(+) ion in eV is