A particle doing simple harmoonic motion amplitude `= 4 cm` time peiod `= 12sec` The ratio between time taken by it in going from its mean position to `2cm ` and from `2cm` to exterme position is

A particle doing simple harmonic motion amplitude = 4 cm time period = 12sec The ratio between time taken by it in going from its mean position to 2cm and from 2cm to extreme position is

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

A particle executing a simple harmonic motion has a period of 6 sec.The time taken by the particle to move from the mean position to half the amplitude is

A particle is perfroming simple harmoic motion along x-"axis" with amplitude 4 cm and time period 1.2 sec .The minimum time taken by the particle to move from x=2 cm to x= + 4 cm and back again is given by

A particle is performing simple harmonic motion along x- axis with amplitude 4 cm and time period 1.2 sec .The minimum time taken by the particle to move from x = 2 cm to x = +4 cm and back again is given by

The periodic time of a particle doing simple harmonic motion is 4 second . The time taken by it to go from its mean position to half the maximum displacement (amplitude) is

A particle is executing simple harmonic motion of amplitude 12 cm and time period 3 s. Calculate the time required by the particle to move between two points 6 cm on either side of mean position.