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cos 20^@.cos 40^@.cos 60^@ cos 80^@=...

`cos 20^@.cos 40^@.cos 60^@ cos 80^@=`

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Prove that cos 20^@ cos 40^@ cos60^@ cos80^@=1/16

Prove the following : cos20^@.cos40^@.cos60^@.cos80^@ = 1/16

Find the value of cos20^@. cos40^@. Cos60^@. Cos80^@

cos20^(@).cos40^(@).cos60^(@).cos80^(@) is :

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

Prove that cos 20^(@)cos40^(@)cos60^(@)cos80^(@)=(1)/(16)

Prove that, cos20^@cos40^@cos60^@cos80^@=1/16

Prove the following: cos20^@cos40^@cos60^@cos80^@=1/16

A=cos 20^(@)cos 40^(@) cos60^(@)cos 80^(@) , B=cos6^(@)cos42^(@)cos66^(@)cos78^(@) and C=cos 36^(@)cos72^(@)cos 108^(@)cos 144^(@) then