`[(251)^(98)+(21)^(29)-(106)^(100)+(705)^(35)-16^(4)+259]` इकाई का अंक हैं।

The digit in the units place of [(251)^(98)+backslash(21)^(29)-backslash(106)^(100)+(705)^(35)-16^(4)+backslash259] is 1(b)4(c)5(d)6

Write each of the following beleow in set- builder form: (i) A ={1, (1)/(4),(1)/(9),(1)/(16),(1)/(25),(1)/(36),(1)/(49)} (ii) B ={ (1)/(2),(2)/(5),(3)/(10),(4)/(17),(5)/(26),(6)/(37),(7)/(50)} (iii) B ={53,59,61,71,79} (iv) D={-1,1} (v) E={14,21,28,35,42,...,98}

If A=[(10,6),(-4,8)] and I_2=[(1,0),(0,1)] then AI_2 is equal to a) [(10,6),(-4,8)] b) [(21,-16),(-12,15)] c) [(1,1),(1,1)] d) [(1,0),(0,1)]

Fill in the blanks: (i) (-23)/(17)xx (18)/(35)= (18)/(35) xx (.......) (ii) -38xx(-7)/(19)=(-7)/(19)xx (.....) (iii) ((15)/(7)xx (-21)/(10)) xx (-5)/(6) = (........) xx ((-21)/(10) xx (-5)/(6)) (iv) (-12)/(5) xx ((4)/(15)xx (25)/(-16))=((-12)/(5)xx (4)/(15))xx(........)

Find: (i) the 20th term of the AP 9, 13, 17, 21, … (ii) the 35 th term of the AP 20, 17, 14, 11,… (iii) the 18th term of the AP sqrt(2), sqrt(18), sqrt(50), sqrt(98),… (iv) the 9th term of the AP (3)/(4), (5)/(4), (7)/(4), (9)/(4),.... (v) the 15th term of the AP -40, -15, 10, 35,....

If frac(1)(x+frac(1)(y+frac(2)(z+frac(1)(4)))) = 29/79 where x,y and z are natural numbers, then the value of (2x + 3y -z)is: यदि फ़्रेक (1) (x + फ़्रेक (1) (y + फ़्रेक (2) (z + फ़्रेक (1) (4)))) = 29 / 79 जहाँ x, y और z प्राकृतिक संख्याएँ हैं, तब (2x + 3y -z) का मान है:

EXAMPLE 1. Simplify: (i) frac(7)(15) div frac(2)(3) (ii) frac(-8)(35) div frac(2)(7) (iii) frac(16)(21) div frac(-4)(3) (iv) frac(-9)(20) div frac(-3)(10)