The potential energy between two atoms in a molecule is given by
`U=ax^(2)-bx^(2)`
where `a` and `b` are positive constants and `x` is the distance between the atoms. The atom is in stable equilibrium when `x` is equal to `:-`

The potential energy between two atoms in a molecule is given by U(x)= (a)/(x^(12))-(b)/(x^(6)) , where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibrium when

The potential energy between two atoms in a molecule is given by, U_((x))=(a)/x^(12)-(b)/x^(6) , where a and b are positive constant and x is the distance between the atoms. The atoms is an stable equilibrium, when-

The potential energy between two atoms in a molecule is given by U(x)= (1)/(x^(12))-(b)^(x^(6)) , where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibirum when

The potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x) =a/x^(12)-b/x^(6) where a and b are constant and x is the distance between the atoms. Find the dissoociation energy of the molecule which is given as D=[U(x- infty)-U_(at equilibrium)]

The potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x) =a/x^(12)-b/x^(6) where a and b are constant and x is the distance between the atoms. Find the dissoociation energy of the molecule which is given as D=[U(x- infty)-U_(at equilibrium)]

In a molecule, the potential energy between two atoms is given by U(x)=(a)/(x^(12))-(b)/(x^(6)) . Where a and b are positive constants and x is the distance between atoms. Find the value of x at which force is zero and minimum P.E. at that point.

In a molecule, the potential energy between two atoms is given by U (x) = (1)/(x^(12)) -(b)/(x^(6)) . Where 'a' and 'b' are positive constants and 'x' is the distance between atoms. Find the value of 'x' at which force is zero and minimim P.E at that point.