A physical quantity P is related to four observables A, B, C and D as `P=4pi^(2)A^(3)B^(2)//(sqrt(C)D)`
the percentage error of the measurement in A, B, C and D are 1%,3% and 2%, 4% respectively. Determine the percenrage error & absolute error in the quantity P. Value of P is calculated 3.763.

A physical quantity P is related to four observables A, B, C and D as P=4pi^(2)A^(3)B^(2)//(sqrt(C)D) . The percentage error of the measurement in A, B, C and D are 1%, 3%, 2% and 4% respectively. The percentage error is 2a% and absolute error in the quantity P is b/2 . Find 'a' and 'b' if value of P is 3.57.

A physical quantity P is related to four observables a, b, c and d as follows: P = (a^(3)b^(2))/(dsqrt(c)) The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2% respectively. What is the percentage errors in the quantity P?

A physical quantity P is related to four observables a, b, c and d as follows: P = (a^(3)b^(3))/(sqrt(cd)) The percentage errors of measurement in a,b, c and d are 1%, 3%, 4%, and 2% respectively. What is the percentage error in the quantity P? If the value of P calculated using the given relation turns out to be 3.763, to what value should the result be rounded off?