If `vecA+vecB=vecC`, then magnitude of `vecB` is

If vecA = vecB + vecC and the magnitudes of vecA, vecB and vecC are 5,4 and 3 units respecetively, the angle between vecA and vecC is :

For any two vectors vecA and vecB, if vecA*vecB=|vecAxxvecB| , the magnitude of vecC=vecA+vecB is equal to

For the any two vecrtors vecA and vecB , if vecA.vecB=|vecAxxvecB| , the magnitude of vecC=vecA+vecB is equal to

The magnitudes of vectors vecA,vecB and vecC are 3,4 and 5 units respectively. If vecA+vecB= vecC , the angle between vecA and vecB is

Three vectors vecA,vecB and vecC are such that vecA=vecB+vecC and their magnitudes are in ratio 5:4:3 respectively. Find angle between vector vecA and vecB

The magnitudes of vectors vecA,vecB and vecC are 3,4 and 5 units respectively. If vecA+vecB= vecC , the angle between vecA and vecB is

Given : vecC=vecA+vecB . Also , the magnitude of vecA,vecB and vecC are 12,5 and 13 units respectively . The angle between vecA and vecB is

The magnitudes of vectors vecA.vecB and vecC are respectively 12,5 and 13 unira and vecA+vecB=vecC , then the angle between vecA and vecB is :