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A curve satisfies the differential equat...

A curve satisfies the differential equation `(dy)/(dx)=(x+1-xy^2)/(x^2y-y)` and passes through `(0,0)` (1) The equation of the curve is `x^2+y^2+2x=x^2y^2` (2) The equation of the curve is `x^2+y^2+2x+2y=x^2y^2` (3) `x=0` is a tangent to curve (4) `y=0` is a tangent to curve

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