A hot fbody placed in air is cooled down according to Newton's law of cooling, the rate of decrease of temperature being k times the temperature difference from the surrounding. Starting from `t=0` , find the time in which the body will loss half the maximum heat it can lose.

A hot body placed in air is cooled down according to Newton's law of cooling, the rate of decrease of temperature being k times the temperature difference from the surrounding. Starting from t=0 , find the time in which the body will lose half the maximum heat it can lose.

A hot body placed in air is cooled down according to Newtons Law of cooling, the rate of decrease of temperature being beta times the temperature difference from the surrounding. Starting from t = 0, the time in which the body will loose half the maximum heat it can loose,

A hot body placed in air is cooled down according to newton's law of cooling the rate of decrease of temperature being k times the temperature difference from the surrounnding Starting from t =0 The time in which the body will lose half of the maximum heat is (xLn2)/(2k) Find the value of x .

Derive Newton's law of cooling to show that the rate of loss of heat from the body is proportional to the temperature difference between the body and its surroundings.

According to Newton's law of cooling, the rate of cooling of a body is proportional to (Deltatheta)^(n),"where "Deltatheta is difference of temperature of body and surroundings, and n is equal to