A projectile thrown with a speed v at an angle `theta` has a range R on the surface of earth. For same v and `theta`, its range on the surface of moon will be

A particle projected from earth with speed u and angle with ground theta covers range R. The new range for same mu and theta at moOn is

A projectile is thrown with a speed v at an angle theta with the vertical. Its average velocity between the instants it crosses half the maximum height is

A projectile is thrown with a speed v at an angle theta with the vertical. Its average velocity between the instants it crosses half the maximum height is

A projectile is thrown at an angle theta with the horizontal and its range is R_(1) . It is then thrown at an angle theta with vertical anf the range is R_(2) , then

A projectile is thrown at an angle theta with the horizontal and its range is R_(1) . It is then thrown at an angle theta with vertical anf the range is R_(2) , then

A projectile thrown with an initial speed u and the angle of projection 15^@ to the horizontal has a range R . If the same projectile is thrown at an angle of 45^@ to the horizontal with speed 2 u , what will be its range ?

A projectile thrown with an initial speed u and the angle of projection 15^@ to the horizontal has a range R . If the same projectile is thrown at an angle of 45^@ to the horizontal with speed 2 u , what will be its range ?

A projectile fired with initial velocity u at some angle theta has a range R . If the initial velocity be doubled at the same angle of projection, then the range will be

A projectile fired with initial velocity u at some angle theta has a range R . If the initial velocity be doubled at the same angle of projection, then the range will be

A projectile fired with initial velocity u at some angle theta has a range R . If the initial velocity be doubled at the same angle of projection, then the range will be