Two wire of the same meta have same length, but their cross-sections are in the rati `3:1` . They are joined in series. The resistance of thicker wire is `10Omega` . The total resistance of the combination will be

Two wires of the same metal have same length, but their cross-sections are in the ratio 3:1 . They are joined in series. The resistance of thicker wire is 10 Omega . The total resistance of the combination will be

Two wires of the same metal have the same length, but their cross-sections are in the ratio of 3:1 . They are joined in series. The resistance of the thicker wire is 10 Omega . The total resistance of the combinations will be

Two wires of same metal have the same length but their cross- sections are in the ratio 1 :3 . They are joined in series. The resistance of the thicker wire is 10 Omega . The total resistance of the combination will be

Two wires of the same metal have the same length, but their cross-sections are in the ratio of 3:1. They are joined in series. The resistance of the thicker wire is 10 Omega . The total resistance of the combinations will be

Choose correct alternative. Two wires of same material and same length are connected in series. The area of cross section of wires is in ratio 3:1 . The resistance of thicker wire is 10 Omega . The total resistance of combination is

Two wires A and B of the same material have their lengths in the ratio 1 : 5 and diameters in the ratio 3 : 2 . If the resistance of the wire B is 180 Omega , find the resistance of the wire A.

Two wires have same length. But area of cross-section of one is 4 times that of the other. If the resistance of thinner wire be 200 Omega the resistance of the thicker wire is