The probabilities of three events `A ,B ,a n dC` are `P(A)=0. 6 ,P(B)=0. 4 ,a n dP(C)=0. 5.` If `P(AuuB)=0. 8 ,P(AnnC)=0. 3 ,P(AnnBnnC)=0. 2 ,a n dP(AuuBuuC)geq0. 85 ,` then find the range of `P(BnnC)dot`

If P(A)=0. 3 ,\ P(B)=0. 6 ,\ P(B//A)=0. 5 , find P(AuuB) .

If A, B, C are events such that P(A)=0.3,P(B)=0.4,P(C )=0.8 P(AnnB)=0.08,P(AnnC)=0.28 P(AnnBnnC)=0.09 If P(AuuBuuC)ge0.75 , then find the range of x=P(BnnC) lies in the interval.

The probabilites fo three events A, B and C are given by P(A) = 0.6, P(B) = 0.4 and P(C) = 0.5 . If P(AuuB) = 0.8 , P(A nnC) = 0.3 P(Ann BnnC) = 0.2, P(B nn C) = beta and P(A uu B uu C) = alpha where 0.85 le alpha le 0.95 , then beta lines in the interval :

A,B,C are three events for which P(A)=0. 4 ,P(B)=0. 6 ,P(C)=0. 5 ,P(AuuB)=0. 75 ,P(AnnC)=0. 30 and P(AnnBnnC)=0. 2 , if P(AuuBuuC)geq0. 75 , then P(BnnC) can take values 0.1 (b) 0.2 (c) 0.3 (d) 0. 5

The probabilities of three events A,B,C are such that P(A)=0.3, P(B)=0.4, P(C)=0.8,P(A nn B)=0.09, P(Ann C) = 0.28, P(A nn B nn C) 0.08 and P(Auu B uu C) leq 0.75.Show that P(B nn C) lies in the interval [0.21, 0.46].

If P(A)=0.6,P(B)=0.5 and P(A//B)=0.3 , then find P(A uu B) .

If P(A)=0. 4 ,\ P(B)=0. 8 ,\ P(B//A)=0. 6 . Find P(A//B) and P(AuuB)

If P(A)=0.3,P(B)=0.6,P(B//A)=0.5 , find P(A uu B) .

If P(A)=0. 8 ,P(B)=0. 5 ,a n dP(B//A)=0. 4 , find (i) P(AnnB) (ii)P(A/B) (iii)P(AuuB)

If P(A)=0. 4 ,\ P(B)=0. 3\ a n d\ P(B//A)=0. 5 , find P(AnnB)\ a n d\ P(A//B)dot