Home
Class 12
MATHS
Consider two curves C1: y^2=4[sqrt(y)]x ...

Consider two curves `C_1: y^2=4[sqrt(y)]x a n dC_2: x^2=4[sqrt(x)]y ,` where [.] denotes the greatest integer function. Then the area of region enclosed by these two curves within the square formed by the lines `x=1,y=1,x=4,y=4` is `8/3s qdotu n i t s` (b) `(10)/3s qdotu n i t s` `(11)/3s qdotu n i t s` (d) `(11)/4s qdotu n i t s`

Promotional Banner

Similar Questions

Explore conceptually related problems

The area bounded by the curve y^2=8x\ a n d\ x^2=8y is (16)/3s qdotu n i t s b. 3/(16)s qdotu n i t s c. (14)/3s qdotu n i t s d. 3/(14)s qdotu n i t s

The area of the region enclosed between the curves x=y^2-1a n dx=|y|sqrt(1-y^2) is 1s qdotu n i t s (b) 4/3s qdotu n i t s 2/3s qdotu n i t s (d) 2s qdotu n i t s

The area bounded by the curve a^2y=x^2(x+a) and the x-axis is (a^2)/3s qdotu n i t s (b) (a^2)/4s qdotu n i t s (3a^2)/4s qdotu n i t s (d) (a^2)/(12)s qdotu n i t s

The area bounded by the two branches of curve (y-x)^2=x^3 and the straight line x=1 is 1/5s qdotu n i t s (b) 3/5s qdotu n i t s 4/5s qdotu n i t s (d) 8/4s qdotu n i t s

The area of the region bounded by x=0,y=0,x=2,y=2,ylt=e^x a n dygeq1nx is 6-41n2s qdotu n i t s (b) 41n2-2s qdotu n i t s 21n2-4s qdotu n i t s (d) 6-21n2s qdotu n i t s

The area bounded by the curve f(x)=x+sinx and its inverse function between the ordinates x=0a n dx=2pi is 4pis qdotu n i t s (b) 8pis qdotu n i t s 4s qdotu n i t s (d) 8s qdotu n i t s

The minimum area of circle which touches the parabolas y=x^2+1 and y^2=x-1 is (9pi)/(16)s qdotu n i t (b) (9pi)/(32)s qdotu n i t (9pi)/8s qdotu n i t (d) (9pi)/4s qdotu n i t

The area of the region (s) enclosed by the curves y = x^(2) and y= sqrt(abs(x)) is

Let f(x)=m in i mu m(x+1,sqrt(1-x)) for all xlt=1. Then the area bounded by y=f(x) and the x-axis is 7/3s qdotu n i t s 1/6s qdotu n i t s (11)/6s qdotu n i t s (d) 7/6s qdotu n i t s