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Solve ydx-xdy+logxdx=0...

Solve `ydx-xdy+logxdx=0`

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Knowledge Check

  • The curve satisfying ydx-xdy+logxdx=0 (xgt0) passing through (1, -1) is

    A
    `y+logx+1=0`
    B
    `-y^2+logx+1=0`
    C
    `y^3+(logx)^2+1=0`
    D
    none of these

  • The solution of the differential equation ydx-xdy+lnxdx=0 is (where, C is an arbitrary constant)

    A
    `y=(ln x)^(2)+C`
    B
    `y=(ln x+1)+C`
    C
    `y=-( ln x+1)+C`
    D
    `y=(lnx)(x+C)`

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