Twelve balls are distributed among three boxes, find the probability that the first box will contains three balls.

Twelve balls are distribute among three boxes. The probability that the first box contains three balls is a.(110)/9(2/3)^(10) b. (110)/9(2/3)^(10) c. (^(12)C_3)/(12^3)xx2^9 d. (^(12)C_3)/(3^(12))

If 8 balls are distributed at random among three boxes,what is the probability that the first box would contain 3 balls?

Twelve balls are placed in three boxes. The probability that the first box contains three balls is

The probability that when 12 distinct balls are distributed among three distinct boxes, the first will contain exactly three balls is

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is :

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is :

15 identical balls are placed in 3 different boxes, find the probability that each box contain at least 3 balls is p than 34p =