Find the area of the closed figure bounded by the curves `y=sqrt(x),y=sqrt(4-3x)a n dy=0`

The area bounded by the curves y=-sqrt(-x) and x=-sqrt(-y) where x,y<=0

The area of the closed figure bounded by the curves y=cosx,y =1+(2)/(pi)x and x=pi//2, is

Find the area of the region bounded by the curve y=x^(3),y=x+6" and "x=0

The area bounded by the curves y=-sqrt(-x) and x=-sqrt(-y) where x,yle0

Find the area of the region bounded by the curves y=sqrt(x+2) and y=(1)/(x+1) between the lines x=0 and x=2.

Find the area of the region bounded by the curves 2y^2=x, 3y^2=x+1, y=0 .

Find the area of the region bounded by the curves x^(2)+y^(2)=4 , y=sqrt(3)x and x -axis in the first quadrant.

Find the area of the figure bounded by the curve y=sin^-1x , the lines x=0 and y=pi/2 .

Using integration find the area of the region bounded by the curves y=sqrt(4-x^(2)),x^(2)+y^(2)-4x=0 and the x- axis.

Find the area of the region bounded by the curves y=x^(2)+2y=x,x=0 and x=3