A `4 Omega` non insulated resistance wire is bent in the middle by `180^@` and both the halves are twisted with each other. What will be its new resistance ?

A 8 Omega resistance wire is bent through 180^(@) at its mid point and the two halves are twisted together. Then the resistance is

The resistance of a wire is R. It is bent at the middle by 180^@ and both the ends are twisted together to make a shorter wire. The resistance of the new wire is

A wire of resistance 4 Omega is bent through 180^@ at its mid point and the two halves are twisted together. Then the resistance is

A piece of wire of resistance 4Omega is bent through 180^(@) at its midpoint and the two halves are twisted together.Then the resistance is

A piece of wire of resistance 4Omega is bent through 180^(@) at its midpoint and the two halves are twisted together. Then the resistance is

A piece of wire of resistance 4 ohm is bent through 180 at its mid point and the two halves are twisted together. Then the resistance is

A piece of wire of resistance 4 ohm s is bent through 180^(@) at its mid point and the two halves are twisted together, then the resistance is

A piece of wire of resistance 4 ohm s is bent through 180^(@) at its mid point and the two halves are twisted together, then the resistance is

A given wire of resistance 1 Omega is stretched to double its length. What will be its new resistance ?