A parallel plate capacitor is connected to a battery as shown in figure. Consider two situations :
.
A : Key `K` is kept closed and plates of capacitors are moved apart using insulting handle.
B : Key `K` is opened and plates of capacitors are moved apart using insulting handle. Choose the correct options (s).

Options

A. In A Q remains same but C changes.
B. In B V remains same but C changes
C. In A V remains same and hence Q changes.
D. In B Q remains same and hence V changes.

Answer

C

Explanation

Case A when key K is kept closed and paltes of capacitors are moved apart using insulating handle, the separation between two plates increases which in turn decreases its capacitance `(C=(Kepsi_(0)A)/(d))` and hence, the charge stored decreases as Q=CV (potential continue to be the same as capacitor is still connected with cell).
Case B when key K is opened and plates of capacitors are moved apart using insulating handle, charge stored by disconnected charged capacitor remains conserved and with the decreases of capacitance, potential difference V increases as V=Q/C.