Find the locus of the foot of the perpendicular drawn from the center upon any tangent to the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1.`

The locus of the foot of the perpendicular drawn from the centre on any tangent to the ellipse x^2/25+y^2/16=1 is:

If the locus of the foot of the perpendicular drawn from centre upon any tangent to the ellipse (x^(2))/(40)+(y^(2))/(10)=1 is (x^(2)+y^(2))^(2)=ax^(2)+by^(2) , then (a-b) is equal to

If the locus of the foot of the perpendicular drawn from centre upon any tangent to the ellipse (x^(2))/(40)+(y^(2))/(10)=1 is (x^(2)+y^(2))^(2)=ax^(2)+by^(2) , then (a-b) is equal to

The locus of the foot of the perpendicular from the foci an any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 , is

The locus of the foot of the perpendicular from the foci an any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 , is

Find the locus of the foot of the perpendicular drawn from a fixed point to any tangent to a parabola.