A child weighing 25 kg slides down a rope hanging from the branch of a tall tree. If the force of friction acting against him is 2 N , what is the acceleration of the child

A child weighing 25 kg slides down a rope hanging from a branch of a tall tree. If the force of friction acting against him is 200 N, the acceleration of child is (g=10 m//s^(2))

A child weighing 25 kg slides down a rope hanging from a branch of a tall tree. If the force of friction acting against him is 200 N, the acceleration of child is (g=10 m//s^(2))

A boy of weight 25kg slides down a rope hanging from the branch of a tree. If the force of friction against him is 50N, the boy's acceleration is (g= 10 ms^(-2) )

A boy of weight 25kg slides down a rope hanging from the branch of a tree. If the force of friction against him is 50N, the boy's acceleration is (g= 10 ms^(-2) )

A body weighing 20 kg just slides down a rough plane that rises 5 in 12. What is the coefficient of friction?

A body weighing 20kg just slides down a rough inclined plane that rises 5 in 12. What is the coefficient of friction ?

A body weighing 20 kg just slides down a rough inclined plane that rises 5 m in every 12 m.What is the coefficeint of friction?