`6.02xx10^(20)` molecules of urea are present in 100 ml of its solution. The concentration of solution is :

Options

A. 0.02 M
B. 0.01 M
C. 0.001 M
D. 0.1 M

Answer

B

Explanation

Given , number of molecules of urea `=6.02xx10^(20)`
`:.` Number of moles `=(6.02xx10^(20))/(N_(A))`
`=(6.02xx10^(20))/(6.023xx10^(23))=0.999xx10^(-3)=1xx10^(-3)"mol"`
Volume of the solution
`=100mL=(100)/(1000)L=0.1L` Concentration of urea solution (in mol `L^(-1))`
`=(1xx10^(-3))/(0.1)"mol " L^(-1)`
`=1xx10^(-2)"mol " L^(-1)`
`=0.01 "mol " L^(-1)`