If the density of water is 1 g `cm^(-3)` then the volume occupied by one molecule of water is approximately

Options

A. `9.0xx10^(-23)cm^(3)`
B. `6.023xx10^(-23)cm^(3)`
C. `3.0xx10^(-23)cm^(3)`
D. `5.5xx10^(-23)cm^(3)`

Answer

C

Explanation

1 mole `=6.023xx10^(23)` molecule
`18g=6.02xx10^(23)` molecule
18 g = mass of `6.02xx10^(23)` water molecules Mass of one water molecule `=(18)/(6.023xx10^(23))g`
Density `=1 g cm^(-3)`
volume `=("Mass of one water molecule")/("Density")`
`=(18)/(6.023xx10^(23)xx1)cm^(3)`
`~~3.0xx10^(-23)cm^(3)`