What volume of oxygen gas `(O_(2))` measured at `0^(@)C` and 1 atm is needed to burn completely `1 L` of propane gas `(C_(3)H_(8))` measured under the same condition?

Options

A. 7 L
B. 6 L
C. 5 L
D. 10 L

Answer

C

Explanation

`{:(C_(3)Hg,+,5O_(2),to,3CO_(2),+,4H_(2)O),(22.4L,,5xx22.4L,,,,):}`
For the combustion of 22.4 L propane , oxygen required `=5xx22.4 L`
For the combustion of 1 L of propane
Oxygen required `=(5xx22.4)/(22.4)L= 5 L`