In Haber process 30 litre of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only`50%` of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end ?

Options

A. 20 L ammonia , 10 L nitrogen , 30 L hydrogen
B. 20 L ammonia , 25 L nitrogen , 15 L hydrogen
C. 20 L ammonia , 20 L nitrogen , 20 L hydrogen
D. 10 L ammonia , 25 L nitrogen , 15 L hydrogen

Answer

D

Explanation

`underset(10 L)underset(1 V)(N_(2))+underset(30L)underset(3V)(3H_(2))tounderset(20 L)underset(2V)(2NH_(3))`
As only `50%` of the expected product is formed, hence only 10 L of `NH_(3)` is formed.
Thus , for the production of 10 L of `NH_(3)` , 5 L of `N_(2) and 15 L` of `H_(2)` are used and composition of gaseous mixture under the aforesaid condition in the end is
`H_(2)=30-15=15 L`
`N_(2)=30-5 =25 L`
`NH_(3)=10 L`