Which has maximum number of molecules?

Options

A. `7 gN_(2)`
B. `7 g H_(2)`
C. `16 g NO_(2)`
D. `16 g O_(2)`

Answer

B

Explanation

In 7 g nitrogen , number of molecules `=(7.0)/(28) "mol"`
`=0.25xxN_(A)` molecules
where , `N_(A)=` Avogadro number `=6.023xx10^(23)`
in 2 g of `H_(2)=(2.0)/(2)" mol" =1xxN_(A)` molecules
in 16 g of `NO_(2)=(16.0)/(46)" mol" `
" " `0.348xxN_(A)`molecules
In 16 g of `O_(2)=(16)/(32) " mol " =0.5xxN_(A)` molecules
Hence , maximum number of molecules are present in 2 g of `H_(2)`.