Percentage of Se in peroxidase anhydrase enzyme is `0.5%` by weight (at. Wt. `=78.4)`, then minimum molecular weight of peroxidase anhydrase enzyme is:

Options

A. `1.568xx10^(3)`
B. `15.68`
C. `2.168xx10^(4)`
D. `1.568xx10^(4)`

Answer

D

Explanation

Suppose the molecular weight of enzyme` =x 0.5%` by weight means in 100 g of enzyme weight of Se =0.5 g
`:.` in x g of enzyme weight of Se `=(0.5)/(100)xxX`
Hence, `78.4=(0.5xxx)/(100)`
`X=15680=1.568xx10^(4)`