The number of atoms in `4.25 g NH_(3)` is approximately:

Options

A. `4xx10^(23)`
B. `2xx10^(23)`
C. `1xx10^(23)`
D. `6xx10^(23)`

Answer

D

Explanation

Weight of `NH_(3)=4.25 g`
Number of moles of `NH_(3)=("Weight")/("Molecular weight")`
`=(4.25)/(17)=0.25"mol "`
Number of molecules in 0.25 mole of `NH_(3)`
`=025xx6.023xx10^(23)`
So , number of atoms `=4xx0.25xx6.023xx10^(23)`
`=6.0xx10^(23)`