In the reaction, `4NH_(3)(g)+5O_(2)(g) rarr 4NO(g)+6H_(2)O(g)`, when 1 mole of ammonia and 1 mole of `O_(2)` are made to react to completion

Options

A. 1.0 mole of `H_(2)O` is produced
B. 1.0 mole of NO will be produced
C. all the oxygen will be consumed
D. all the ammonia will be consumed

Answer

C

Explanation

`underset(" 4 mol")(4NH_(3)(g))+underset("5 mol")(5O_(2)(g))tounderset("4 mol")(4NO(g))+underset("6 mol")(6H_(2)O(1))`
According to equation ,
5 moles of `O_(2)` required = 4 moles of ` NH_(3)`
1 mole of `O_(2)` requires `=(4)/(5)=0.8` mole of `NH_(3)` While 1 mole of `NH_(3)` requires `=(5)/(4) = 1.25 " moles of " O_(2)`
As there is 1 mole of `NH_(3)` and 1 mole of `O_(2)` , so all the oxygen will be consumed .