If `0.24 g` of a volatile liquid upon vaporization gives `45 ml` of vapors at `NTP`, what will be the vapor density of the substance? (Density of `H_(2) = 0.089 f L^(-1)`)

Options

A. 95.93
B. 59.93
C. 95.39
D. 5.993

Answer

B

Explanation

Weight of gas =0.24g
Volume of gas (V) -45 mL -0.45 L
Density of `H_(2)`(d) =0.089
Weight of 45 mL of `H_(2)=Vxxd=0.045xx0.089`
`4.005xx10^(-3)` g
Therefore , vapour density
`=("Weight of certain volume of substance")/("Weight of same volume of hydrogen")`
`=(024)/(4.005xx10^(-3))=59.93`