The number of oxygen atoms in 4.4 of `CO_(2)` is

Options

A. `1.2xx10^(23)`
B. `6xx10^(22)`
C. `6xx10^(23)`
D. `12xx10^(23)`

Explanation

To find the number of oxygen atoms in 4.4 grams of carbon dioxide (CO₂), we can follow these steps:

### Step 1: Determine the molar mass of CO₂
The molar mass of carbon dioxide (CO₂) can be calculated using the atomic masses of carbon and oxygen:
- Atomic mass of carbon (C) = 12 g/mol
- Atomic mass of oxygen (O) = 16 g/mol

Since CO₂ contains 1 carbon atom and 2 oxygen atoms, the molar mass is calculated as follows:
\[ \text{Molar mass of CO₂} = (1 \times 12) + (2 \times 16) = 12 + 32 = 44 \text{ g/mol} \]

### Step 2: Calculate the number of moles of CO₂ in 4.4 grams
Using the molar mass, we can find the number of moles of CO₂ in 4.4 grams:
\[ \text{Number of moles of CO₂} = \frac{\text{mass}}{\text{molar mass}} = \frac{4.4 \text{ g}}{44 \text{ g/mol}} = 0.1 \text{ moles} \]

### Step 3: Determine the number of moles of oxygen atoms
Since each mole of CO₂ contains 2 moles of oxygen atoms, we can calculate the number of moles of oxygen:
\[ \text{Number of moles of O} = 2 \times \text{Number of moles of CO₂} = 2 \times 0.1 = 0.2 \text{ moles of O} \]

### Step 4: Convert moles of oxygen to atoms
To find the number of oxygen atoms, we use Avogadro's number, which is \(6.022 \times 10^{23}\) atoms/mole:
\[ \text{Number of oxygen atoms} = \text{Number of moles of O} \times \text{Avogadro's number} = 0.2 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole} \]
\[ = 1.2044 \times 10^{23} \text{ oxygen atoms} \]

### Step 5: Round the answer
Rounding \(1.2044 \times 10^{23}\) gives approximately \(1.2 \times 10^{23}\) oxygen atoms.

### Final Answer
The number of oxygen atoms in 4.4 grams of CO₂ is approximately \(1.2 \times 10^{23}\) atoms.

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