The van't hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is

Options

A. 0
B. 1
C. 2
D. 3

Answer

D

Explanation

Key Idea - Strong electrolytes dissociate completely in their solutions.
van't Hoff factor = total number of ions after dissociation
So for `{:(Ba(OH)_(2)hArr Ba^(2)(aq)+2OH^(-)(aq)),("Number of ions 1 2"):}`
van't Hoff factor, i = 1+2 =3