How many grams of a dibasic acid (mol. Mass `200`) should be present in `100 mL` of the aqueous solution to give `0.1 N` solution.

Options

A. 1 g
B. 2 g
C. 10 g
D. 20 g

Answer

A

Explanation

Equivalent weight of dibasic acid
`=("Molecular weight")/(2)`
`E=(200)/(2)=100`
Stremgth `=0.1N, m = ? V = 100 mL`
Normality (N) `=("Mass")/(E )xx(1000)/(V(L))`
`w=(E NV)/(1000)=(100xx100xx0.1)/(1000)=1g`