If solution containing `0.15 g` of solute dissolved in `15 g` of solvent boils at a temperature higher by `0.216^(@)C` than that of pure solvent, the molecular mass of the substance is `(K_(b)=2.16^(@)C)`

Options

A. `1.01`
B. 10
C. `10.1`
D. 100

Answer

D

Explanation

`w=0.15 g, W = 15 g, Delta T_(b)=0.216^(@)C`
`K_(b)=2.16, m=?`
`m=(1000xxK_(b))/(Delta T_(b))xx(w)/(W)=(1000xx2.16xx0.15)/(0.216xx15)=100`